How to get to the element value if it has an attribute (XDTO)

How to define XDTO package to obtain the value of element if it has an attribute?
Example XML:

<id_lang xlink:href="http://example.com/api/languages/2">
<![CDATA[ 2 ]]>
</id_lang>

ExType = XDTOFactory.Type("http://www.sample-package.org", "example");
Object = XDTOFactory.ReadXML(XMLReader, ExType);

Sorry, forum doesn't permit to post XML. There is just one element, it has a string attribute and the value of element is 2. Nothing more

Try setting the Form property value to Attribute for your package property which should be read from the XML element attribute.

I did that, but it was not enough. I found out that you also have to add another property with the name __content to the type definition but this was not enough too.
It seems to me the problem is with namespaces, because the xml file have an xlink namespace and I use import directive to point out but if I make a xsd-file exporting the XDTO-package it uses other letters (ns1 instead of xlink) to describe a namespace, and I have not found where you could define the representation of namespace for attribute.
I will continue to search around although at this point Id like to kill someone.

Please provide XML with data and XML XSD schema (note that you can write and use import for XSD schemas) so we could reproduce your situation.

Please, see XML Schema Examples.

Murat Yazlıyev posted his solution.

It is alive.
Murat's post could be the solution to my initial problem, but I have found that there were no way i could define prefix for namespace so i had to give up.