Hello,

I created an Android service. It's package is "com.test.servicetest". Service class is "MyService". How can I run this service from 1C mobile ?

I tried this way, but it won't run :

#If MobileAppClient Then
   Application = New MobileDeviceApplicationRun();
   Application.Action = "com.test.servicetest.MyService";
   Application.Run(True);
#Endif

Hello, Sebi Dan!

The syntax is correct.

Can you run your service class from other mobile application? Are you sure it is working outside 1C platform?

Hello,

I tried to run the service from other android application and it starts with no problem. Android code used is this :

            Intent intent = new Intent(Intent.ACTION_MAIN);
            intent.setComponent(new ComponentName("com.test.servicetest", "com.test.servicetest.MyService"));
            startService(intent);

Hello, Sebi Dan!

MobileDeviceApplicationRun stands for Activity.startActivityForResult(Intent, RequestCode)

Also, in your case you need to initialize MobileDeviceApplicationRun with "android.intent.action.MAIN" because you did it in your example of running in other program:

   Application = New MobileDeviceApplicationRun("android.intent.action.MAIN");
   Application.Action = "com.test.servicetest.MyService";
   Application.Run(True);

Hello, Timofey !

I tried like you said but it won't run the service.  I think it is bug here. The code runs with no errors, but it does nothing. I am using 1C:Enterprise 8.3 (8.3.8.1652) and 1C:Enterprise 8.3(8.3.8.58) ( Android ).

A few moments ago I tried creating the *.xml file on desktop using 8.3.9 and run it on mobile ( 8.3.9.74 ) and the result is the same, no service started.

I sent you a private message with all the details. Thank you !

There are two ways for this:

• Create empty Activity without displaying it, in OnCreate start the service if it is not started and close activity. Please note that the best practice is to inform a user when the service is started.
  
• Use the mobile platform 8.3.9, create an external component that will call startService.